Question

Помогите пж ооочень срочно

Answer 1

Ответ:

1)

$\frac { c ^ { 6 } } { 6 y ^ { 4 } } - \frac { c } { 12 y ^ { 3 } }$

$\frac{2c^{6}}{12y^{4}}-\frac{cy}{12y^{4}}$

$\frac{2c^{6}-cy}{12y^{4}}$

$\frac{c\left(2c^{5}-y\right)}{12y^{4}}$

2)

$\frac { m + 3 } { 5 m ^ { 3 } n } + \frac { 2 n ^ { 2 } - 3 } { 10 m n }$

$\frac{6+2\left(mn\right)^{2}+2m-3m^{2}}{10nm^{3}}$

3)

$\frac { 3 x + 2 } { 5 x } - \frac { 5 x + 3 y } { 10 x y } - \frac { y - 1 } { 2 y }$

$\frac{\left(3x+2\right)\times 2y}{10xy}-\frac{5x+3y}{10xy}-\frac{y-1}{2y}$

$\frac{\left(3x+2\right)\times 2y-\left(5x+3y\right)}{10xy}-\frac{y-1}{2y}$

$\frac{6xy+4y-5x-3y}{10xy}-\frac{y-1}{2y}$

$\frac{6xy-5x+y}{10xy}-\frac{y-1}{2y}$

$\frac{6xy-5x+y}{10xy}-\frac{\left(y-1\right)\times 5x}{10xy}$

$\frac{6xy-5x+y-\left(y-1\right)\times 5x}{10xy}$

$\frac{6xy-5x+y-5xy+5x}{10xy}$

$\frac{xy+y}{10xy}$

$\frac{y\left(x+1\right)}{10xy}$

$\frac{x+1}{10x}$