Question

Пожалуйста помогите дам 70б

Answer 1

Ответ:

$log ^{2} _{3}(x) - log_{ \frac{1}{9} }(x) - 5 = 0 \\ log {}^{2} _{3}(x) - log_{ {3}^{ - 2} }(x) - 5 = 0 \\ log {}^{2} _{3}(x) + \frac{1}{2} log_{3}(x) - 5 = 0 \\ 2 log {}^{2} _{3}(x) + log_{3}(x) - 10 = 0 \\ log_{3}(x) = y \\ 2 {y}^{2} + y - 10 = 0 \\ d = 1 + 80 = 81 \\ y1 = \frac{ - 1 + 9}{4} = 2 \\ y2 = \frac{ - 1 - 9}{4} = \frac{ -10 }{4} = - \frac{5}{2} \\ log_{3}(x) = 2 \\ x = {3}^{2} \\ x = 9 \\ log_{3}(x) = - \frac{5}{2} \\ x = {3}^{ - \frac{5}{2} } \\ x = \sqrt{ {3}^{5} }$