Question

$tg ^{2} x - 2tgx - 3 = 0$
Ребят, помогите с уравнением плиз✊​

Answer 1

Ответ:

$\tan(x) = y \\ {y}^{2} - 2y - 3 = 0 \\ d = 4 + 12 = 16 \\ y1 = \frac{2 + 4}{2} = 3 \\ y2 = \frac{2 - 4 }{2} = - 1 \\ \tan(x) = 3 \\ x = arctg(3) + \pi \: n \\ \tan(x) = - 1 \\ x = - \frac{\pi}{4} + \pi \: n$