Question

Помогите пожалуйста решить,даю 100 баллов

Answer 1

Ответ:

1.

1

$\sqrt{9 \times 1.14} = \sqrt{ \frac{9 \times 114}{100} } = \frac{3 \sqrt{114} }{10}$

2

$\sqrt{8} \times \sqrt{18} = \sqrt{8 \times 9 \times 2} = \\ = \sqrt{ {4}^{2} \times {3}^{2} } = 4 \times 3 = 12$

3

$\frac{ \sqrt{27} }{ \sqrt{3} } = \sqrt{ \frac{27}{3} } = \sqrt{9} = 3$

4

$\sqrt{ {2}^{4} \times {5}^{2} } = {2}^{2} \times 5 = 4 \times 5 = 20$

2.

1

$\sqrt{3} ( \sqrt{27} - \sqrt{48}) = \sqrt{3} \times \sqrt{27} - \sqrt{3} \times \sqrt{48} = \\ = \sqrt{ {3}^{4} } - \sqrt{ 3 \times 3 \times 16} = {3}^{2} - 3 \times 4 = 9 - 12 = - 3$

2

$(1 - \sqrt{3} )(2 + \sqrt{3} ) = 2 + \sqrt{3} - 2 \sqrt{3} - {( \sqrt{3} )}^{2} = \\ = 2 - \sqrt{3} - 3 = - 1 - \sqrt{3}$

3

$( \sqrt{2} - 2 \sqrt{10} )(2 \sqrt{10} + \sqrt{2} ) = \\ = {( \sqrt{2} )}^{2} - {(2 \sqrt{10}) }^{2} = 2 - 4 \times 10 = \\ = 2 - 40 = - 38$