Question

Помогите пожалуйста, прошу! ТОЛЬКО 17.2

Answer 1

Ответ:

17.2

а)

$f'(x) = 2 + \frac{2}{ { \cos}^{2} (x)}$

б)

$f'(x) = (4x) '\times ctgx + (ctgx) '\times 4x = \\ = 4ctgx - \frac{1}{ { \sin }^{2}(x) } \times 4x = \\ = 4ctgx - \frac{4x}{ { \sin }^{2}(x) }$

в)

$f'(x) = \cos(x + \frac{\pi}{3} ) \times (x + \frac{\pi}{3} )' = \\ = \cos(x + \frac{\pi}{3} ) \times 1 = \cos(x + \frac{\pi}{3} )$

г)

$f'(x) = \frac{1}{ { \cos}^{2} (x + \frac{\pi}{4} )} \times (x + \frac{\pi}{4} ) '= \frac{1}{ { \cos}^{2}(x + \frac{\pi}{4} ) }$