Предмет: Геометрия, автор: AkulovaAlisa

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В треугольнике АВС А В =90°. Биссектриса угла А пересекает катет ВС под углом 74°. Найдите острые углы треугольника АВС

Ответы

Автор ответа: Achola89LoZ
1

Ответ:

угол =90-74=16 градусов

угол =16*2=32 градуса

угол =90-32=58 градусов

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