Question

2sin37,5•cos37,5•cos75

Answer 1

Объяснение:

$2*sin37,5^0*cos37,5^0*cos75^0=sin(2*37,5^0)*cos75^0=sin75^0*cos75^0=\\=\frac{2*sin75^0*cos75^0}{2} =\frac{sin(2*75^0)}{2}=\frac{sin150^0}{2}=\frac{\frac{1}{2} }{2}=\frac{1}{4} .$