Question

(2/3)^((5x^2)-29)=(2/3)^(-x^2-5)

Answer 1

$(2/3)^{((5x^2)-29)}=(2/3)^{(-x^2-5)}$
$5x^2-29=-x^2-5$
$5x^2 - x^2=29-5$
$6x^2=24$
$x^2=4$
$x_{1,2}= pm 2$