Предмет: Геометрия, автор: frizorgeranastasia34

помогите пожалуйста срочно!!!!!​

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Ответы

Автор ответа: saidsofiya567
0

Ответ:

126:

1) 120 2) 80

127:

1) 36 2)34


frizorgeranastasia34: а можно по подробней и с чертежам (полную версию задания)
Автор ответа: dos1axgod
1

Ответ:

126.

a)<N=180°-(<K+<M)=180°-(35°+25°)=120°

б)<D=180°-(<P+<F)=180°-(40°+60°)=80°

127.

a)<A=<C=72°(ABC-равнобедренный треугольник)B=

<B=180°-(<A+<C)=180°-(72°+72°)=36°

b)<N=<K=(180°-<M)÷2=(180°-112°)÷2=34°

<N=34°,<K=34°

128.

a)<MKN=180°-147°=33°

<KMN=180-84°=96°

<N=180-(<MKN+<KMN)=180°-(33°+96°)=51°

b)<BAC=180°-109°=71°

<BCA=180°-153°=27°

<B=180°-(<BAC+<BCA)=180°-(71°+27°)=102°


frizorgeranastasia34: спасибо
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