Question

Решите систему неравенств:
2(x+3) – 3(х-2) > 0,
2х + 3(2x – 3) <7.​

Answer 1

1)

$2(x + 3) - 3(x - 2) > 0 \\ 2x + 6 - 3x + 6 > 0 \\ - x + 12 > 0 \\ x < 12 \\ x( - \infty ;12)$

2)

$2x + 3(2x - 3) < 7 \\ 2x + 6x - 9 < 7 \\ 8x - 9 < 7 \\ 8x < 16 \\ x < 2 \\ x( - \infty ;2)$