Question

log1/3(x-3)>2
решите неравенства​

Answer 1

ОДЗ :

x - 3 > 0      ⇒    x > 3

$log_{\frac{1}{3}}(x-3)>2\\\\0<\frac{1}{3} <1 \ \Rightarrow \ x-3<(\frac{1}{3})^{2}\\\\x-3<\frac{1}{9}\\\\x<3\frac{1}{9}\\\\Otvet:\boxed{x\in(3 \ ; \ 3\frac{1}{9})}$