Question

помогите срочно!!!! пожалуйста. Даю 20 баллов​

Answer 1

( 1 )

$-2,8+x+5,36+(-7,2)+y+(-7,36)=-2,8+x+5,36-7,2+y-7,36= \\\\=x+y-2,8+5,36-7,2-7,36=x+y+2,56-7,2-7,36\\\\=x+y-4,64-7,36=x+y-12$

При x = -13 и y = 54

$x+y-12=-13+54-12=41-12=29$

( 2 )

$m+(-2\frac{4}{9})+8\frac{13}{24}+n+(-3\frac{2}{9})+(-4\frac{5}{24})=m-2\frac{4}{9}+8\frac{13}{24}+n-3\frac{2}{9}-4\frac{5}{24}= \\\\=m-\frac{22}{9}+\frac{205}{24}+n-\frac{29}{9}-\frac{101}{24}= m-\frac{22}{9}+\frac{205}{24}+n-\frac{29}{9}-\frac{101}{24} =\\\\= m-\frac{176}{72}+\frac{615}{72}+n-\frac{232}{72}-\frac{303}{72}= m+n-\frac{176}{72}+\frac{615}{72}-\frac{232}{72}-\frac{303}{72}=\\\\=m+n+\frac{439}{72}-\frac{232}{72}-\frac{303}{72}=m+n+\frac{207}{72}-\frac{303}{72}=m+n-\frac{96}{72}=$

$=m+n-\frac{12}{9}=m+n-\frac{4}{3}=m+n-1\frac{1}{3}$

При  $m=-3\frac{5}{6}$  и $n=-2\frac{11}{12}$

$m+n-1\frac{1}{3}=-3\frac{5}{6}-2\frac{11}{12}-1\frac{1}{3}= -\frac{23}{6}-\frac{35}{12}-\frac{4}{3} =-\frac{46}{12}-\frac{35}{12}-\frac{16}{12}=-\frac{81}{12}-\frac{16}{12}=\\\\=-\frac{97}{12}=-8\frac{1}{12}$