Question

Помогите пожалуйста!

Answer 1

Ответ:

${(2tg \frac{\pi}{6} + 3ctg \frac{\pi}{3}) }^{2} = {(2 \frac{ \sin( \frac{\pi}{6} ) }{ \cos( \frac{\pi}{6} ) } + 3 \frac{ \cos( \frac{\pi}{3} ) }{ \sin( \frac{\pi}{3} ) } )}^{2} = \\ = {(2 \times \frac{1}{2} \times \frac{2}{ \sqrt{3} } + 3 \times \frac{1}{2} \times \frac{2}{ \sqrt{3} } )}^{2} = \\ = {( \frac{2}{ \sqrt{3} } + \frac{3}{ \sqrt{3} } )}^{2} = {( \frac{5}{ \sqrt{3} } )}^{2} = \frac{25}{3}$