Question

Разложите на множители x^2+2xy+y^2-64​

Answer 1

(x+y)^2-64
(x+y-8)*(x+y+8)

Answer 2

$x {}^{2} +2 xy + y {}^{2} - 64 = (x + y) {}^{2} - 64 = (x + y - 8) \times (x + y + 8)$