Question

вычислить 2log6 2+log6 9

Answer 1

$2 log_{6} 2 + log_{6} 9= log_{6} 2^{2} + log_{6} 9 = log_{6} 4 + log_{6} 9 = log_{6} (4*9) = log_{6}36$

$log_{6}36 = log_{6} 6^{2} = 2$

Answer 2

2log6 2+log6 9=log6 2^2+log6 9=log6 4*9=log6 36= log6 6^2=2
loga bc= loga b +loga c