Question

помогите пожалуйста
с математикой​

Answer 1

( 1 )

$x+8\frac{5}{6}=10\frac{1}{3}\\\\x+\frac{53}{6}=\frac{31}{3}\\\\x=\frac{31}{3}-\frac{53}{6}\\\\x=\frac{62}{6}-\frac{53}{6}\\\\x=\frac{9}{6} \\\\x=\frac{3}{2}\\\\x=1,5$

Проверка:

$1,5+8\frac{5}{6}=10\frac{1}{3}\\\\\frac{1,5}{1}+\frac{53}{6}=\frac{31}{3}\\\\\frac{9}{6}+\frac{53}{6}=\frac{62}{6}\\\\\frac{62}{6}=\frac{62}{6}\\\\10\frac{2}{6}=10\frac{2}{6}\\\\10\frac{1}{3}=10\frac{1}{3}$

( 2 )

$11\frac{7}{9}+y=13 \frac{1}{18}\\\\\frac{106}{9}+y=\frac{235}{18}\\\\y=\frac{235}{18}-\frac{106}{9}\\\\y=\frac{235}{18}- \frac{212}{18}\\\\y=\frac{23}{18}\\\\y=1\frac{5}{18}$

Проверка:

$11\frac{7}{9}+1\frac{5}{18}=13\frac{1}{18}\\\\\frac{106}{9}+\frac{23}{18}=\frac{235}{18}\\\\\frac{212}{18}+\frac{23}{18}=\frac{235}{18}\\\\\frac{235}{18}=\frac{235}{18}\\\\13\frac{1}{18}=13\frac{1}{18}$

( 3 )

$x-24\frac{2}{7}=16 \frac{3}{8}\\\\x- \frac{170}{7}=\frac{131}{8}\\\\x=\frac{131}{8}+\frac{170}{7} \\\\x=\frac{917}{35}+\frac{1360}{35}\\\\x= \frac{2277}{35}\\\\x=65\frac{2}{35}$

Проверка:

$65\frac{2}{35}-24\frac{2}{7}=16\frac{3}{8}\\\\\frac{2277}{35}-\frac{170}{7}= \frac{131}{8}\\\\\frac{2277}{25}-\frac{1360}{35}= \frac{917}{35}\\\\\frac{917}{35}=\frac{917}{35}\\\\26,2=26,2$

( 4 )

$60\frac{2}{5}-y=57\frac{3}{4}\\\\\frac{302}{5}-y=\frac{231}{4}\\\\-y=\frac{231}{4}-\frac{302}{5}\\\\y=\frac{302}{5}-\frac{231}{4}\\\\y=\frac{1208}{20} -\frac{1155}{20}\\\\y=\frac{53}{20}\\\\y=2\frac{13}{20}$

Проверка:

$60\frac{2}{5}-2\frac{13}{20}=57\frac{3}{4}\\\\\frac{302}{5}-\frac{53}{20}=\frac{231}{4}\\\\\frac{1208}{20}-\frac{53}{20}=\frac{1155}{20}\\\\\frac{1155}{20}=\frac{1155}{20}\\\\57\frac{15}{20}=57\frac{15}{20} \\\\57\frac{3}{4}=57\frac{3}{5}$