Question

решите систему:
2x+2y-xy-4=0
xy=60

Answer 1

2x+2y-xy-4=0
xy=60
2x+2y-60-4=0
x+y=32
x=32-y
y(32-y)=60
y^2-32y+60=0
y12=(32+-корень(1024-240))/2=(32+-28)/2= 2 30
x=2
y=30
x=30
y=2