Question

Помогите: 

X^2+y=12

Знак системы

X+y^2=12

Answer 1

$x^2+y=12\ x+y^2=12\\ x^2+y=x+y^2\ x^2-y^2=x-y\ (x+y)(x-y)=x-y\ (x-y)(x+y-1)=0\ x=y\ x^2+x-12=0\ D=1+4*1*12=7^2\ x=frac{-1+7}{2}=3\ x=frac{-1-7}{2}=-4\ y=3\ y=-4\ \ x=1-y\ (1-y)^2+y=12\ 1-2y+2y^2=12\ 2y^2-2y-11=0\ D=4+4*2*11=sqrt{92}\ y=frac{2+sqrt{92}}{4}\ y=frac{2-sqrt{92}}{4}\ x=frac{2-sqrt{92}}{4}\ x=frac{2+sqrt{92}}{4}$