Question

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Answer 1

$dfrac{x^2+2x+1}{|x+1|}-x=dfrac{(x+1)^2}{|x+1|}-x=dfrac{|x+1|^2}{|x+1|}-x=|x+1|-x\ |x+1|-x=begin{cases}1,&xgeqslant-1\-1-2x,& x<-1end{cases}$