Question

x^2+10x+25=
36y^2-49=
(2x+5) (x+6) +2 (3x+2) (3x-2)=


(^2 это в квадрате)​

Answer 1

Объяснение:

${x}^{2} + 10x + 25 =(x + 5 {)}^{2}$

$36 {y}^{2} - 49 = (6y - 7)(6y + 7)$

$(2x + 5)(x + 6) + 2(3x + 2)(3x - 2) = 2 {x}^{2} + 12x + 5x + 30 + 2(9 {x}^{2} - 4) = 2 {x}^{2} + 17x + 30 + 18 {x}^{2} - 8 = 20 {x}^{2} + 17x + 22$