Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!!!
ДАЮ 30 БАЛЛОВ

Answer 1

Ответ:

Объяснение:

3)$(x^{2}-2x) ^{2} +12(x-1)^{2} -1=0$

$x^{4} -4x^{3} +4x^{2} +12(x-1)^{2}-1=0$

$x^{4} -4x^{3} +4x^{2} +12(x^{2} -2x-1)-1=0$

$x^{4} -4x^{3} +4x^{2} +12x^{2} -24x+12-1=0$

$x^{4} -x^{3} -3x^{3} 4x^{2} 12x^{2} -24x+12-1=0$

$x^{4} -x^{3} -3x^{3} +16x^{2} -13x-11x+12-1=0$$x^{4} -x^{3} -3x^{3} +3x^{2} +13x^{2} -13x-11x+11=0$

$x^{3} *(x-1)-3x^{2} *(x-1)+13x*(x-1)-11(x-1)=0$

(x-1)*($x^{3} -3x^{2} +13x-11$)=0

$(x-1)*(x-1)*(x^{2} -2x+11)=0$

$(x-1)^{2} *(x^{2} -2x+11)=0$

$(x-1)^{2} =0$

$x^{2} -2x+11=0$

x=1

4)$3x^{3} +13x^{2} +13x+3=0$

$3(x^{3}+1)* (x^{2} -x+1)+13x*(x+1)=0$

$3(x+1)*(x^{2} -x+1)+13x*(x+1)=0$

$(x+1)*(3(x^{2} -x+1)+13x)=0$

$(x+1)*(3x^{2} -3x+3+13x)=0$

$(x+1)*(3x^{2} +10x+3)=0$

$(x+1)*(3x^{2} +9x+x+3)=0$

$(x+1)*(3x*(x+3)+x+3)=0$

$(x+1)*(x+3)*(3x+1)=0$

x+1=0

x+3=0

3x+1=0

x=-1

x=-3

x=-$\frac{1}{3}$