Question

Задание 3,4 помогите пожалуйста

Answer 1

3a) A + B = (–2a² + 3ab – 4b²) + (3a² – 4ab + 5b²) = (–2a² + 3a²) + (3ab – 4ab) + (–4b² + 5b²) = a² – ab + b²

3б) A – B = (–2a² + 3ab – 4b²) – (3a² – 4ab + 5b²) = (–2a² – 3a²) + (3ab + 4ab) + (–4b² – 5b²) = –5a² + 7ab – 9b²

3в) B – A = (3a² – 4ab + 5b²) – (–2a² + 3ab – 4b²) = (3a² + 2a²) + (–4ab – 3ab) + (5b² + 4b²) = 5a² – 7ab + 9b²

4а) y·yx – x²y = –x²y + xy²

4б) 3b·2a·7c + 7 – b·5a = 42abc – 5ab + 7

4в) 6x·(–0,5y)·7x² + (–0,9x)·7y² = –21x³y – 6,3xy²