пожалуйста решите с графиками

Ответы
Ответ:
Объяснение:
1. (x+12)(x-3) > 0
x + 12 = 0
x - 3 = 0
x = -12
x = 3
y(0) = (0+12)(0-3) = 12×(-3) = -36
y(-15) = (-15 + 12)(-15-3) = -3×(-18) = 54
y(4) = (4+12)(4-3) = 16×1 = 16
x∈ (-∞; -12)∪(3; +∞)
2. x(x-5)(8-x)(x+3) ≤ 0
x=0
x-5 = 0
x = 5
8-x =0
-x = -8
x = 8
x + 3 = 0
x = -3
y(-4) = -4(-4-5)(8 - (-4))(-4 + 3) = -4×(-9)×12×(-1) = -432
y(-1) = -1(-1-5)(8-(-1))(-1+3) = 108
y(1) = 1(1-5)(8-1)(1+3) = -112
y(6) = 7(7-5)(8-7)(7+3) = 140
y(9) = 9(9-5)(8-9)(9+3) = -432
x∈ (-∞; -3]∪[0; 5]∪[8; +∞)
3. (x+1)(3-x)(x-2) < 0
x+1=0
x = -1
3-x = 0
-x = -3
x = 3
x-2 = 0
x = 2
y(-2) = (-2+1)(3-(-2))(-2-2) = 20
y(0) = (0+1)(3-0)(0-2) = -6
y(2.5) = (2.5 +1)(3-2.5)(2.5 -2) = 0.875
y(4) = (4+1)(3-4)(4-2) = -10
x∈ ( -1; 2)∪( 3; +∞)
4. (x+8)(x-4) ≥ 0
x+8 = 0
x = -8
x - 4 = 0
x = 4
y( -10) = (-10 + 8)( - 10 - 4) = 28
y(0) = (0+8)(0-4) = -32
y(5) = (5+8)(5-4) = 13
x∈ (-∞; -8]∪[4; +∞)



