Question

Даю 20баллов!!!!!!!!!!!

Answer 1

Вот правильно!!!!!!!!!!

Answer 2

Ответ:

$x(3+i)^2+y(1-i)^2=4+2i\\\\x(9+6i+i^2)+y(1-2i+i^2)=4+2i\\\\x(8+6i)+y(-2i)=4+2i\\\\8x+(6x-2y)i=4+2i\ \ \ \Rightarrow \ \ \ \left\{\begin{array}{l}8x=4\\6x-2y=2\end{array}\right\ \ \left\{\begin{array}{l}x=0,5\\3-2y=2\end{array}\right\\\\\left\{\begin{array}{l}x=0,5\\y=0,5\end{array}\right$