Question

$2 {}^{x {}^{2} + x - 0.5} = 4 \sqrt{2}$
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Answer 1

Ответ:

$2^{x^2+x-0,5}=4\sqrt2\\\\2^{x^2+x-0,5}=2^{\frac{5}{2}}\\\\x^2+x-0,5=\dfrac{5}{2}\\\\x^2+x-3=0\\\\D=1+12=13\ \ ,\ \ \ x_1=\dfrac{-1-\sqrt{13}}{2}\ \ ,\ \ x_2=\dfrac{-1+\sqrt{13}}{2}$