Question

решите уравнение
а) (х-1)(х+1)=2(х-3)²-х²
Б) (2х+3)²-4(х-1)(х+1)=49​

Answer 1

a) (x-1)(x+1)=2(x-3)²-x²

x²-1²=2(x²-6x+9)-x²

x²-1-2x²+12x-18+x²=0

12x-19=0

12x=19

x=19/12

$x = 1 \frac{7}{12}$

b) (2x+3)²-4(x-1)(x+1)=49

4x²+9+12x-4(x²-1²)=49

4x²+9+12x-4x²+4-49=0

12x-36=0

12x=36

x=3