Question

Алгебра 10 класс помогите))

Answer 1

Ответ:

$( \frac{1}{3} ) {}^{ - 2x + 5} \times ( \frac{1}{3} ) {}^{ - 6x + 7} = \frac{1}{81} ; \\ ( \frac{1}{3} ) {}^{ - 2x + 5 - 6x + 7} = \frac{1}{3 {}^{4} } ; \\ ( \frac{1}{3} ) {}^{ - 8x + 12} = 3 {}^{ - 4} ; \\ 3 {}^{8x - 12} = 3 {}^{ - 4} ; \\ 8x - 12 = - 4; \\ 8x = - 4 + 12; \\ 8x = 8; \\ x = 8 \div 8; \\ x = 1.$