Question

4^x - 12 * 2^x + 32 >=0

Answer 1

4^x-12*2^x+32>=0
2^x=t
t^2-12t+32>=0
t12=(12+-корень(144-4*32))/2=(12+-4)/2= 8 4
(t-4)(t-8)>=0

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t<=4
t>=8
2^x<=4
x<=2
2^x>=8
x>=3
ответ (-бесконечность 2] U [3 +бесконечность)