Question

По формуле разности квадратов двух выражений (4+m) (4-m)=

Answer 1

$1)(4+m)(4-m)=4^{2}-m^{2}=\boxed{16-m^{2}}\\\\2)4-m^{2} =2^{2}-m^{2}=\boxed{(2-m)(2+m)}\\\\3)75^{2}-25^{2}=(75-25)(75+25)=50*100=\boxed{5000}\\\\4)(\frac{7}{9})^{2}-(\frac{2}{9})^{2}=(\frac{7}{9}-\frac{2}{9})(\frac{7}{9}+\frac{2}{9})=\frac{5}{9}*1=\boxed{\frac{5}{9}}\\\\5)(200-1)(200+1)=200^{2}-1^{2}=40000-1=\boxed{39999}$