Question

Алгебра, 10 класс. Логарифмы
Решить 9,11, 13

Answer 1

Ответ:

9.

${3}^{1 + log_{3}(16) } = 3 \times {3}^{ log_{3}(13) } = 3 \times 16 = 48$

11.

${4}^{3 - log_{4}(8) } = {4}^{3} \times {4}^{ - log_{4}(8) } = \\ = 64 \times \frac{1}{ {4}^{ log_{4}(8) } } = 64 \times \frac{1}{8} = 8$

13.

$log_{2}(25.6) + log_{2}(5) = log_{2}(25.6 \times 5) = \\ = log_{2}(128) = 7$