Question

2x²+2(3x+2)(3x-2)=5(2x+1)² уравнение решите пж побыстрее!​

Answer 1

Ответ:

$x = - \frac{13}{20} \\ x = - 0.65$

Объяснение:

$2x {}^{2} + 2(9x {}^{2} - 4) = 5(4x {}^{2} + 4x + 1 \\ 2x {}^{2} + 18 {}^{2} - 8 = 20x {}^{2} + 20x + 5 \\ 20x {}^{2} - 8 = 20x {}^{2} + 20x + 5 \\ - 8 = 20x + 5 \\ - 20x = 5 + 8 \\ - 20x = 13 \\ x = - \frac{13}{20}$

Answer 2

$2x^2+2(3x+2)(3x-2)=5(2x+1)^2$

$2x^2+2(9x^{2} -4)=5(4x^{2} +4x+1)$

$2x^2+18x^{2} -8=20x^{2} +20x+5$

$20x^{2} -8-20x^{2} -20x-5=0$

$-20x-13=0$

$-20x=13$

$x=13:(-20)$

$x=-0,65$