Question

Помогите пожалуйста ​

Answer 1

Ответ:

a)

$\sin( \alpha ) = \frac{1}{2} \\ \alpha 1 = \frac{\pi}{6} \\ \alpha 2 = \frac{5\pi}{6}$

$\sin( \alpha ) = - \frac{ \sqrt{2} }{2} \\ \alpha1 = \frac{5\pi}{4} \\ \alpha 2 = \frac{7\pi}{4} \\ \\ \sin( \alpha ) = \frac{ \sqrt{3} }{2} \\ \alpha1 = \frac{\pi}{3} \\ \alpha 2 = \frac{2\pi}{3}$

$\sin( \alpha ) = - 1 \\ \alpha = \frac{3\pi}{2}$

$\sin( \alpha ) = 0 \\ \alpha = \pi$

б)

$\cos( \alpha ) = 1 \\ \alpha = 0 \\ \\ \cos( \alpha ) = - \frac{ \sqrt{3} }{2} \\ \alpha 1 = \frac{5\pi}{6} \\ \alpha 2 = \frac{7\pi}{6} \\ \\ \cos( \alpha ) = 0 \\ \alpha1 = \frac{\pi}{2} \\ \alpha 2 = \frac{3\pi}{2} \\ \\ \cos( \alpha ) = \frac{ \sqrt{2} }{2} \\ \alpha1 = \frac{\pi}{4} \\ \alpha 2 = \frac{7\pi}{4}$

в)

$tg( \alpha ) = - 1 \\ \alpha1 = \frac{3\pi}{4} \\ \alpha 2 = \frac{7\pi}{4} \\ \\ tg( \alpha ) = \sqrt{3} \\ \alpha1 = \frac{\pi}{3} \\ \alpha 2 = \frac{4\pi}{3} \\ \\ tg( \alpha ) = - \frac{ \sqrt{3} }{3} \\ \alpha 1 = \frac{5\pi}{6} \\ \alpha 2 = \frac{11\pi}{6} \\ \\ tg( \alpha ) = 0 \\ \sin( \alpha ) = 0 \\ \alpha 1= 0 \\ \alpha 2 = \pi$