Question

СРОЧНО! ДАЮ 40 БАЛЛОВ!

Answer 1

Ответ:  C) .

$C)\ \ x^3-3x^2-x+4=0\ \ \ \Rightarrow \ \ \ x_1=-1\ ,\ x_2=1\ ,\ x_3=3\\\\\\\left\{\begin{array}{l}x_1+x_2+x_3=3\\x_1x_2+x_1x_3+x_2x_3=-1\\x_1x_2x_3=-3\end{array}\right\ \ \left\{\begin{array}{l}-1+1+3=3\\-1-3+3=-1\\-1\cdot 1\cdot 3=-3\end{array}\right\ \ \left\{\begin{array}{l}3=3\\-1=-1\\-3=-3\end{array}\right$