Question

Помогите решить
(6x^3+10)(5-4x)
(5x^2+1)3cosx
(2x-4)^5
sin(5x-4)

Answer 1

Ответ:

$(6 {x}^{3} + 10)(5 - 4x) = 30 {x}^{3} - 24 {x}^{4} + 50 - 40x \\ (5 {x}^{2} + 1)3 \cos(x ) = 15 {x}^{2} \times \cos(x) + 3 \cos(x) \\ (2x - 4) ^{5} = 32 {x}^{5} - 320 {x}^{4} + 1280 {x}^{3} - 2560 {x}^{2} + 2560x - 1024 \\ \sin(5x - 4) = \sin(5x) \cos(4) - \cos(5x) \sin(4)$