Question

помогите пожалуйста буду очень благодарен

Answer 1

$1. \\ (x - 10) {}^{2} - x(x - 13) = 1 \\ x = 14 \frac{1}{7}$

$2. \\ (4x + 1) {}^{2} - (4x - 1)(4x + 2) = 7 \\ x = 1$

$3. \\ (x + 5) {}^{2} - (2x + 1)(x - 2) = - 25 \\ x1 = \frac{13 - \sqrt{377} }{2} \\ x2 = \frac{13 + \sqrt{377} }{2}$

$4. \\ (5x + 4) {}^{2} + (4x - 3) {}^{2} = 25 \\ x1 = - \frac{16}{41} \\ x2 = 0$