Question

а) 3х2 + 5х – 2 = 0;
Помогите пж ​

Answer 1

$3x^{2} +5x-2=0$

$a=3;b=5;c=-2$

$D=b^{2} -4ac=5^{2} -4*3*(-2)=25+24=49$

$x_{1} =\frac{-b+\sqrt{D} }{2a} =\frac{-5+\sqrt{49} }{6} =\frac{1}{3}$

$x_{2} =\frac{-b-\sqrt{D} }{2a} =\frac{-5-\sqrt{49} }{6} =-2$

Ответ: $x=-2; x=\frac{1}{3}$