Question

1)(6a-3b)^2+(9a+2b)^2
2)b(b-3)-(b-4)^2
3)(12a-b)^2-(9a-b)(16a+2b)
4) x(2x-9)^2-2x(15+x)^2
5) (x+2)^2-(x-3)(x+3)
Помогиите сроочнооо пж пж пж пж пж

Answer 1

Объяснение:

1)

$36 {a}^{2} - 36ab + 9 {b}^{2} + 81 {a}^{2} + 36ab + 4 {b}^{2} = 36 {a}^{2} + 9 {b}^{2} + 81 {a }^{2} + 4 {b}^{2} = 117 {a}^{2} + 13 {b}^{2}$

2)

${b}^{2} - 3b - ( {b}^{2} - 8b + 16) = {b }^{2} - 3b - {b}^{2} + 8b - 16 = 5b - 16$

3)

$144 {a}^{2} - 24ab + {b}^{2} - (144 {a}^{2} + 18ab - 16ab - 2 {b}^{2} ) = 144 {a}^{2} - 24ab + {b}^{2} - 144 {a}^{2} - 18ab + 16ab + 4 {b}^{2} = 24ab + {b}^{2} - 18ab + 16ab + 4 {b}^{2}= 5 {b}^{2} -26ab$

4)

$x(4 {x}^{2} - 36 + 81) - 2x(225 + 30x + {x}^{2} ) = 4 {x}^{3} - 36x + 81x - 450x - 60x^{2} - 2 {x}^{3} = 2 {x}^{3} - 15x - 450$

5)

${x}^{2} + 4x + 4 - ( {x}^{2} + 3x - 3x - 9) = {x}^{2} + 4x + 4 - {x}^{2} - 3x + 3x + 9 = 4x + 13$