Question

32степень(x+8)(x-4)=0,25*128 степень(x+20)/x

Answer 1

Решение ниже ===========

Answer 2

$32 ^frac{x+8}{x-4} =0,25*128^ frac{x+20}{x}$
$2^ frac{5x+40}{x-4} = 2^{-2} *2^ frac{7x+140}{x}$
$frac{5x+40}{x-4} = frac{7x+140}{x} -2$
$frac{5x+40}{x-4} = frac{5x-140}{x}$
$5x^2+40x=5x^2+140x-20x-560$
80x-560=0
x-7=0
x=7