Question

решите уравнения:
1. x(x-5)-(x-3)²<0
2. (4+y)²-y(6+y)>0
3. (17-y)²>y(y-13)-5
4. z(z-10)>(3-z)²
​

Answer 1

Ответ:

$1) {x}^{2} - 5x - {x}^{2} + 6x - 9 < 0 \\ x - 9 < 0 \\ x < 9$

$16 + 8y + {y}^{2} - 6y - {y}^{2} > 0 \\ 2y + 16 > 0 \\ 2y > - 16 \\ y > - 8$

Объяснение:

$289 - 34y + {y}^{2} > {y}^{2} - 13y - 5 \\ - 21y > - 294 \\ y = 14$

${z}^{2} - 10z > 9 - 6x + {z}^{2} \\ - 4z > 9 \\ z < - 2.25$