Question

Помогите пожалуйста срочно

Answer 1

$\frac{ {a}^{2} + 4ab + 4 {b}^{2} }{ {a}^{3} + 8 {b}^{3} + 6 {a}^{2} b + 12a {b}^{2} } \times \frac{2a + 4b}{3} = \\ = \frac{ {(a + 2b)}^{2} }{ {(a + 2b)}^{3} } \times \frac{2(a + 2b)}{3} = \frac{2}{3}$