Question

Помогите решить Докажите числовое равенство (√5)^log5(√2-1)^2+(√3)^log3(√2-2)^2=1

Answer 1

Ответ:

$\star \ \ a^{log_ab}=b\ \ \star \\\\\\(\sqrt5)^{log_5(\sqrt2-1)^2}+(\sqrt3)^{log_3(\sqrt2-2)^2}=5^{\frac{1}{2}\, log_5(\sqrt2-1)^2}+3^{\frac{1}{2}\, log_3(\sqrt2-2)^2}=\\\\\\=5^{log_5(\sqrt2-1)}+3^{log_3(\sqrt2-2)}=(\sqrt2-1)+(\sqrt2-2)=2\sqrt2-3\ne 1$