Question

Срочнооо!! Помогите решить.

Answer 1

$\frac{1}{3-x}=\frac{3}{20}+\frac{1}{x}\\\\\frac{1}{3-x}-\frac{3}{20}-\frac{1}{x}=0\\\\\frac{20x-3x(3-x)-20(3-x)}{20x(3-x)}=0\\\\\frac{20x-9x+3x^{2}-60+20x }{20x(3-x)}=0\\\\\frac{3x^{2}+31x-60 }{20x(3-x)}=0\\\\\left \{ {{3x^{2}+31x-60=0 } \atop {x\neq0 \ x\neq3}} \right.\\\\3x^{2}+31x-60=0\\\\D=31^{2}-4*3*(-60)=961+720=1681=41^{2}\\\\x_{1}=\frac{-31+41}{6}=\frac{10}{6}=1\frac{2}{3}\\\\x_{2}=\frac{-31-41}{6}=-\frac{72}{6}=-12\\\\Otvet:\boxed{1\frac{2}{3} \ ; \ -12}$