Question

плииз

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Answer 1

$(9x^6)^2 * (\frac{1}{2} x^5)^8 = (\frac{3}{4})^4$

$81x^{12} * \frac{1}{256} x^{40} = \frac{81}{256}$

$\frac{81}{256} x^{52} = \frac{81}{256}$

$x^{52} = 1$

x = ±1

x₁ = - 1

x₂ = 1