Question

Найти y¹, если

y=2x⁶+4x-3; y=5x⁷+2x³+4;

y=3x⁵-6x²+x;

y=√x+3x;

y=4x-12;

y=35+8x;

Answer 1

Ответ:

1.

$y' = 2 \times 6 {x}^{5} + 4 = 12 {x}^{5} + 4$

2.

$y' = 3 \times 5 {x}^{4} - 6 \times 2x + 1 = \\ = 15 {x}^{4} - 12x + 1$

3.

$y '= \frac{1}{2} {x}^{ - \frac{1}{2} } + 3 = \frac{1}{2 \sqrt{x} } + 3$

4.

$y' = 4$

5.

$y' = 8$