Question

Lg(x-1)+lg(x+1)=0 плиззз

Answer 1

$lg(x-1)+lg(x+1)=0\ lg((x-1)(x+1))=lg1\ lg(x^2-1)=lg1\ x^2-1=1\ x^2=1+1\ x^2=2\ x=бsqrt2$