Question

(-x-2)в квадрате(x-1)(x+1)=0​

Answer 1

Ответ:

${( - x - 2)}^{2} (x - 1)(x + 1) = 0 \\ \\ {( - x - 2)}^{2} = 0 \\ - x - 2 = 0 \\ x1 = - 2 \\ \\ x - 1 = 0 \\ x2 = 1 \\ \\ x + 1 = 0 \\ x3 = - 1$