Question

4m/m^2 - 1+2/1-m - 1/m+1 Пжжжж​

Answer 1

Объяснение:

$\frac{4m}{m^2-1}+\frac{2}{1-m} -\frac{1}{m+1}=\frac{4m}{(m-1)*(m+1)}-\frac{2}{m-1}-\frac{1}{m+1}=\frac{4m-2*(m+1)-1*(m-1)}{(m-1)*(m+1)}=\\=\frac{4m-2m-2-m+1}{(m-1)*(m+1)} =\frac{m-1}{(m-1)*(m+1)}=\frac{1}{m+1}.$