Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!!!! ДАМ 25 БАЛЛОВ ​

Answer 1

$1)\ \ tg\Big(-\dfrac{5\pi}{4}\Big)=-tg\dfrac{5\pi}{4}=-tg\Big(\pi +\dfrac{\pi}{4}\Big)=-tg\dfrac{\pi}{4}=-1\\\\\\ctg\Big(-\dfrac{5\pi}{4}\Big)=-ctg\dfrac{5\pi}{4}=-ctg\Big(\pi +\dfrac{\pi}{4}\Big)=-ctg\dfrac{\pi}{4}=-1\\\\\\2)\ \ tg\dfrac{23\pi}{6}=tg\Big(4\pi -\dfrac{\pi}{6}\Big)=tg\Big(-\dfrac{\pi}{6}\Big)=-tg\dfrac{\pi}{6}=-\dfrac{\sqrt3}{3}\\\\\\ctg\dfrac{23\pi}{6}=ctg\Big(4\pi -\dfrac{\pi}{6}\Big)=ctg\Big(-\dfrac{\pi}{6}\Big)=-ctg\dfrac{\pi}{6}=-\sqrt3$

$3)\ \ tg\Big(-\dfrac{22\pi}{3}\Big)=-tg\dfrac{22\pi}{3}=-tg\Big(7\pi +\dfrac{\pi}{3}\Big)=-tg\dfrac{\pi}{3}=-\sqrt3\\\\\\ctg\Big(-\dfrac{22\pi}{3}\Big)=-ctg\dfrac{22\pi}{3}=-ctg\Big(7\pi +\dfrac{\pi}{3}\Big)=-ctg\dfrac{\pi}{3}=-\dfrac{\sqrt3}{3}\\\\\\4)\ \ tg\Big(-\dfrac{23\pi}{4}\Big)=-tg\dfrac{23\pi}{4}=-tg\Big(6\pi -\dfrac{\pi}{4}\Big)=-tg\Big(-\dfrac{\pi}{4}\Big)=tg\dfrac{\pi}{4}=1$

$ctg\Big(-\dfrac{23\pi}{4}\Big)=-ctg\dfrac{23\pi}{4}=-ctg\Big(6\pi -\dfrac{\pi}{4}\Big)=-ctg\Big(-\dfrac{\pi}{4}\Big)=ctg\dfrac{\pi}{4}=1$