Question

Алгебра.
Задание 1....

Answer 1

Ответ:

$1)\ \ y=x^2-6x-8\, lnx\ \ ,\ \ \ y'=2x-6-\dfrac{8}{x}\\\\\\2)\ \ y=e^{x}\cdot x\ \ ,\ \ \ y'=e^{x}\cdot x+e^{x}=e^{x}\cdot (x+1)\\\\\\3)\ \ y=\dfrac{3x}{x^2+1}\ \ ,\ \ \ y'=\dfrac{3(x^2+1)-3x\cdot 2x}{(x^2+1)^2}=\dfrac{-3x^2+3}{(x^2+1)^2}=\dfrac{3\, (x^2-1)}{(x^2+1)}$