Question

Помогите!!!!!!!!!!!!!!! ​

Answer 1

Ответ:

$\displaystyle -18\frac{3}{8}$

Объяснение:

$\displaystyle \frac{(-1\frac{1}{2})^{3} \cdot (2\frac{2}{3})^{2}}{(-1\frac{1}{7})^{2}}=\frac{(-\frac{3}{2})^{3} \cdot (\frac{8}{3})^{2}}{(-\frac{8}{7})^{2}}=\frac{(-1)^{3} \cdot \frac{3^{3}}{2^{3}} \cdot \frac{8^{2}}{3^{2}}}{(-1)^{2} \cdot \frac{8^{2}}{7^{2}}}=\frac{-1 \cdot \frac{27}{8} \cdot \frac{64}{9}}{1 \cdot \frac{64}{49}}=-\frac{\frac{27 \cdot 64}{8 \cdot 9}}{\frac{64}{49}}=$

$\displaystyle =-\frac{27 \cdot 64 \cdot 49}{8 \cdot 9 \cdot 64}=-\frac{9 \cdot 3 \cdot 49}{8 \cdot 9}=-\frac{3 \cdot 49}{8}=-3 \cdot \frac{49}{8}=-3 \cdot 6\frac{1}{8}=-3 \cdot 6-3 \cdot \frac{1}{8}=$

$\displaystyle =-18-\frac{3}{8}=-(18+\frac{3}{8})=-18\frac{3}{8};$